Given the set: # {2,-1,-3,x,-3,2} #, for what x would the mean of the set be 3?

Answer 1

#x = 21#

The equation is obtained by dividing the total number of elements in the set by the number of elements in the mean.

#"mean" = (2+(-1)+(-3)+x+(-3)+(2))/6 = 3#
#=> (x - 3)/6 = 3#
#=> x - 3 = 18#
#=> x = 21#
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Answer 2

To find the mean of a set of numbers, you sum all the numbers together and then divide by the total count of numbers. In this case, the mean of the set is given as 3.

So, the sum of all numbers in the set is: (2 + (-1) + (-3) + x + (-3) + 2)

This sum equals (2x - 3).

To make the mean of the set equal to 3, you set up the equation:

[\frac{{2x - 3}}{{6}} = 3]

Solve for (x):

[2x - 3 = 18] [2x = 21] [x = \frac{{21}}{{2}}]

Therefore, for the mean of the set to be 3, (x) must equal (\frac{{21}}{{2}}), or 10.5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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