Given the relative abundance of the following naturally occurring isotopes of oxygen: O-16: 99.76%, O-17: 0.037%, and O-18: 0.204%, how would you calculate atomic mass?

Answer 1

#"AAM"=sum("isotope mass"xx"percent Abundance")#

The average atomic mass (#"AAM"#) is calculated by the following expression:
#"AAM"=sum ("isotope mass"xx"percent Abundance")#

As a result, to determine the average oxygen atomic mass:

#"AAM"=(16xx0.9976)+(17xx0.00037)+(18xx0.00204)=16.00 " a.m.u."#
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Answer 2

Add up the results of multiplying each isotope's mass by its abundance.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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