Given the reaction:Na2S2O3(aq) + 4Cl2(g) + 5H2O(aq) --> 2NaHSO4(aq) + 8HCl(aq), how many moles of Na2S2O3 are needed to react with 0.12mol of Cl2?

Answer 1

0.03 mol #Na_2S_2O_3#

We can use the mole ratio to solve this problem. We will assume that we have excess #H_2O# and it won't effect our ratio. We are told that we will react 0.12 mol of #Cl_2# so we will start there.
#0.012 mol Cl_2# X #(1 mol Na_2S_2O_3)/(4 mol Cl_2)#= #0.03 molNa_2S_2O_3#

It is crucial to consider the mole ratio—the number of moles in the balanced equation—while configuring the dimensional analysis.

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Answer 2

According to the balanced chemical equation, the molar ratio between Na2S2O3 and Cl2 is 1:4. Therefore, to react with 0.12 mol of Cl2, you would need 0.03 mol of Na2S2O3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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