Given the reaction at equilibrium #2SO_2(g) + O_2(g) rightleftharpoons 2SO_3(g)#, as the pressure is increased at a constant temperature, will the number of moles of #SO_3(g)# produced decrease, increase, or stay the same? Why?
The number of moles of
The number of moles of gas must drop since we raised the pressure.
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The number of moles of SO3(g) produced will increase because increasing pressure shifts the equilibrium towards the side with fewer moles of gas, in this case, the side with more moles of gas (SO2(g) + O2(g)) to produce more moles of SO3(g), thereby increasing the yield of SO3(g).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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