# Given the following, what is the tension in the string when the nearest mass is a distance of 686 km from the Black hole? #G=6.673×10^-11 m^3kg-1s-2#

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Two masses of 1 kg each are connected by a light, inextensible string of one metre in length. The two masses are now made to approach a Black Hole of mass #8.18×10^30 kg# such that the string connecting them lies along a radius.

Two masses of 1 kg each are connected by a light, inextensible string of one metre in length. The two masses are now made to approach a Black Hole of mass

Let A and B be the masses, where A is closer to the black hole O. Then: The tension is determined by the difference in gravitational force between the two masses.

Enter the numbers now and compute:

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The formula for tension in the string would depend on the gravitational forces acting on the masses and the acceleration due to gravity at that distance from the Black hole. Without this information, it is impossible to calculate the tension in the string near the Black hole. Other details about the system, such as the masses involved and their distances from the Black hole, are also necessary.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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