Given the area of a circle is 64(pi) how do you find the radius of the circle?

Answer 1

See the entire solution process below:

The formula for determining the area of a circle is:

#A = pir^2#
Substituting the value from the problem, #64pi# for #A# and solving for #r# gives:
#64pi = pir^2#
We can divide each side of the equation by #color(red)(pi)#
#(64pi)/color(red)(pi) = (pir^2)/color(red)(pi)#
#(64color(red)(cancel(color(black)(pi))))/cancel(color(red)(pi)) = (color(red)(cancel(color(black)(pi)))r^2)/cancel(color(red)(pi))#
#64 = r^2#
We can now take the square root of each side of the equation to find the radius #r#:
#sqrt(64) = sqrt(r^2)#
#8 = r#
#r = 8#
The radius of the circle is #8#.
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Answer 2

To find the radius of the circle given the area ( 64\pi ), you would use the formula ( A = \pi r^2 ), where ( A ) is the area and ( r ) is the radius. So, you would set ( 64\pi = \pi r^2 ) and solve for ( r ). Dividing both sides by ( \pi ) and taking the square root, you find ( r = \sqrt{64} = 8 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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