# Given that P-31 is the only natural isotope of phosphorus, what is the mass of one P atom and the mass of Avogadro's number of P atoms?

We divide the molar mass by the avocado number to determine the mass of a single phosphorus atom.

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Avogadro's number of phosphorus-31 atoms would have a mass of about 30.9738 grams, and one phosphorus-31 (P-31) atom has an approximate mass of 30.9738 atomic mass units (u).

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The atomic mass of phosphorus-31 ((^{31})P) is approximately 30.9738 atomic mass units (u) or 30.9738 grams per mole (g/mol).

To find the mass of one phosphorus ((^{31})P) atom, we use its atomic mass:

Mass of one phosphorus atom ((^{31})P) = 30.9738 atomic mass units (u) or 30.9738 grams per mole (g/mol).

Avogadro's number, (N_A), is (6.022 \times 10^{23}) atoms/mol.

To find the mass of Avogadro's number of phosphorus atoms, we multiply the mass of one phosphorus atom by Avogadro's number:

Mass of Avogadro's number of phosphorus atoms = (30.9738 , \text{g/mol} \times 6.022 \times 10^{23} , \text{atoms/mol}).

This calculation yields the mass of Avogadro's number of phosphorus atoms.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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