Given: #p(x) = -5absx + abs(-x + 1#, #h(x) = -x^2 - 3x#, and #g(x) = 5 - sqrt(x+30)#, how do you find p(-2)?
Avery AlexanderTo find ( p(-2) ), substitute (-2) for ( x ) in the expression for ( p(x) ):
[ p(-2) = -5 \cdot | -2| + | -(-2) + 1| ]
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Ethan Adkins
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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