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Given #log_b3= 0.5283# and #log_b5=0.7740#, how do you find #log_b(5/3)#?

Answer 1

Lincoln Anderson

#log_b(5/3) = 0.2457#

Remember that #log_b(x/y) = log_bx -log_by#

#log_b(5/3) = log_b5 – log_b3 = 0.7740 - 0.5283#

#log_b(5/3) = 0.2457#

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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