Given #f(n)=n-4# and #g(n)=2n#, how do you find #3f(n)+5g(n)#?

Answer 1

#3f(n)+5g(n)=13n-12#

#f(n)=n-4.............(i)# #g(n)=2n..................(ii)#
To find out: #3f(n)+5g(n)#
Multiply #(i)# by #3#. #3f(n)=3(n-4)# #implies 3f(n)=3n-12...................(iii)#
Multiply #(ii)# by #5#. #5g(n)=5(2n)# #implies 5g(n)=10n......................(iv)#
Now, Add #(iii)# and #(iv)#
#implies 3f(n)+5g(n)=3n-12+10n# #implies 3f(n)+5g(n)=13n-12#
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Answer 2

To find 3f(n) + 5g(n), substitute the functions f(n) and g(n) into the expression and perform the calculations:

3f(n) = 3(n - 4) 5g(n) = 5(2n)

Now, expand and simplify each term:

3(n - 4) = 3n - 12 5(2n) = 10n

Finally, add the two terms together:

3f(n) + 5g(n) = (3n - 12) + (10n) = 3n + 10n - 12 = 13n - 12

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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