Given an open top box with a square base, the box is to have a volume of 6 ft squared . How do you express the surface area as a function of its side, x?
Is the question correct. You have mixed you units. Volume is a cubic measurement so can not be 6 ft squared.
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The surface area ( A ) of the open-top box with a square base, in terms of its side length ( x ), can be expressed as:
[ A(x) = x^2 + 4x ]
Where:
- ( x ) is the side length of the square base.
- ( x^2 ) represents the area of the square base.
- ( 4x ) represents the combined area of the four identical sides of the box.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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