Given: 1.65 L of water added to 112 grams of sodium acetate (#NaC_2H_3O_2#). What is the concentration of the solution?
It makes sense that we assumed that volume would not change following dissolution.
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To find the concentration of the solution, we first need to calculate the number of moles of sodium acetate (NaC2H3O2) using its molar mass, then divide by the total volume of the solution.
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Calculate the molar mass of sodium acetate: Na: 1 atom * 22.99 g/mol = 22.99 g/mol C: 2 atoms * 12.01 g/mol = 24.02 g/mol H: 3 atoms * 1.01 g/mol = 3.03 g/mol O: 2 atoms * 16.00 g/mol = 32.00 g/mol Total molar mass = 22.99 + 24.02 + 3.03 + 32.00 = 82.04 g/mol
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Calculate the number of moles of sodium acetate: Number of moles = mass / molar mass Number of moles = 112 g / 82.04 g/mol ≈ 1.363 moles
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Calculate the total volume of the solution: Total volume = volume of water + volume of sodium acetate solution Total volume = 1.65 L + 0 L (since sodium acetate is in solid form and does not contribute to the volume)
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Calculate the concentration of the solution: Concentration = moles of solute / volume of solution Concentration ≈ 1.363 moles / 1.65 L ≈ 0.826 M
Therefore, the concentration of the solution is approximately 0.826 M.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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