# Functions: Give an appropriate domain for #g(x)# which enables #g^-1(x)# to exist?

##
#g(x) = 1/(x+7)^2#

#g^-1(x) = -1/sqrt(x) - 7#

The questions asks to find a domain for #g(x)# such that it also enables #g^-1(x)# to exist.

My first answer was:

#{y:y>=0}#

but apparently this is wrong. Any help would be much appreciated!

The questions asks to find a domain for

My first answer was:

but apparently this is wrong. Any help would be much appreciated!

The domain of

The range of the function is the domain of the inverse function, and the domain of the function is the range of the inverse function.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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