Fred worked these hours during the week: #8, 4 1/2, 3 3/4, 7 1/2, 4 3/4#. If he is paid $5.15 per hour, how much did he earn?

Answer 1

Fred earns #$146.78# during the week.

As Fred has worked for #8,4 1/2,3 3/4,7 1/2,4 3/4# hours during the week,

total number of hours worked is

#8+4 1/2+3 3/4+7 1/2+4 3/4#
= #8+4+3+7+4+1/2+3/4+1/2+3/4#
= #26+2/4+3/4+2/4+3/4#
= #26+10/4=26+5/2=26+2 1/2=28 1/2# hours
and at #$5.15# per hour
he earns #28xx5.15+1/2xx5.15#
= #28xx5+28xx0.15+2.575#
= #140+4.20+2.575#
= #146.775~=146.78#
Hence Fred earns #$146.78# during the week.
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Answer 2

To find out how much Fred earned, you need to calculate the total number of hours he worked during the week and then multiply that by his hourly wage.

Fred's hours: 8 hours + 4 1/2 hours + 3 3/4 hours + 7 1/2 hours + 4 3/4 hours

First, convert all the mixed numbers to improper fractions: 4 1/2 = 4 + 1/2 = 9/2 3 3/4 = 3 + 3/4 = 15/4 7 1/2 = 7 + 1/2 = 15/2 4 3/4 = 4 + 3/4 = 19/4

Now add up all the hours: 8 + 9/2 + 15/4 + 15/2 + 19/4

To add these fractions, you need a common denominator, which is 4: 8 = 32/4 9/2 = 18/4 15/4 stays the same 15/2 = 30/4 19/4 stays the same

Now add: 32/4 + 18/4 + 15/4 + 30/4 + 19/4 = 114/4 = 28.5 hours

Fred worked a total of 28.5 hours.

To find out how much he earned, multiply the total number of hours by his hourly wage: 28.5 hours × 5.15/hour=5.15/hour = 146.78

Fred earned $146.78.

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Answer 3

To calculate Fred's earnings:

  1. Add up the hours worked: 8 + 4 1/2 + 3 3/4 + 7 1/2 + 4 3/4 = 28.5 hours
  2. Multiply the total hours worked by his hourly rate: 28.5 hours * 5.15/hour=5.15/hour = 146.775
  3. Round the amount to the nearest cent: 146.78Therefore,Fredearned146.78 Therefore, Fred earned 146.78.
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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