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For what values of y is the function undefined: #y=(2x-5)/(x+3)#?

Answer 1

Ethan Adkins

See the explanation

If a function in #x# is undefined then #y# can not take on a value.

If #y# can take on a value then the function is defined.

#y=(2x-5)/(x+3)# is undefined at #x=-3#

If this were to be the case we would have

#y=(-6-5)/0# you are 'not allowed' to have 0 as a denominator. Hence 'undefined'

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Answer 2

Savannah Anderson

Savannah Anderson

The function is undefined when the denominator, x+3, equals zero. Therefore, the function is undefined for x = -3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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