# For what values of x, if any, does #f(x) = sec((-15pi)/8+9x) # have vertical asymptotes?

So this function has vertical asymptotes at the solutions to

Alternatives

So, the solutions are:

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The function f(x) = sec((-15pi)/8+9x) has vertical asymptotes when the value inside the secant function, (-15pi)/8+9x, equals odd multiples of pi/2.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- How do you find the limit of # (1/(h+2)^2 - 1/4) / h# as h approaches 0?
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- What is the limit of #sin((x-1)/(2+x^2))# as x approaches infinity?
- How do you find the limit of #(x+5)/(25-x^2)# as x approaches #5^-#?
- For what values of x, if any, does #f(x) = 1/((x-5)(x+6)) # have vertical asymptotes?

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