For what values of x, if any, does #f(x) = 1/((x+12)(x-6)) # have vertical asymptotes?
A vertical asymptote occurs when the denominator equals 0.
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The function (f(x) = \frac{1}{(x+12)(x-6)}) has vertical asymptotes at the values of (x) where the denominator becomes zero. In this case, the vertical asymptotes occur when (x+12 = 0) or (x-6 = 0), which gives (x = -12) and (x = 6). Therefore, the function has vertical asymptotes at (x = -12) and (x = 6).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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