For what values of x, if any, does #f(x) = 1/((x+1)(x-6)) # have vertical asymptotes?
Christopher Agrestaf(x) will have vertical asymptotes where the denominator equals to zero. That is, where the limit of f(x) will rise or drop without bound.
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The function f(x) = 1/((x+1)(x-6)) has vertical asymptotes at x = -1 and x = 6.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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