# For what values of x, if any, does #f(x) = 1/((2x-3)(7x-6) # have vertical asymptotes?

The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the values that x cannot be and if the numerator is non-zero for these values then they are vertical asymptotes.

By signing up, you agree to our Terms of Service and Privacy Policy

The function f(x) = 1/((2x-3)(7x-6)) has vertical asymptotes at x = 3/2 and x = 6/7.

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- How do you find the limit of #((sqrt(169-x^2))+12)/(x-5)# as x approaches 5?
- What is the limit of #(1 + sqrt3(x))(4 - 2 x^2 + x^3) # as x approaches 8?
- How do you find the limit of #x^sqrtx# as x approaches 0?
- How do you determine one sided limits numerically?
- How do you show that the function #f(x)=1-sqrt(1-x^2)# is continuous on the interval [-1,1]?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7