For the reaction #2HNO_3 + Mg(OH)_2 -> Mg(NO_3)_2 + 2H_2O#, how many grams of magnesium nitrate are produced from 8 moles of water?
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The molar ratio between water and magnesium nitrate in the reaction is 2:1. Therefore, if 8 moles of water are consumed, 4 moles of magnesium nitrate will be produced. To find the mass of magnesium nitrate produced, you need to know its molar mass, which is approximately 148.3 g/mol. So, the mass of magnesium nitrate produced is:
4 moles × 148.3 g/mol = 593.2 grams
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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