For the given point in polar coordinates, how do you find the corresponding rectangular coordinates for the point. (4, -pi/2)?
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To find the corresponding rectangular coordinates for the point ( (4, -\frac{\pi}{2}) ) given in polar coordinates:
[ x = r \cdot \cos(\theta) ] [ y = r \cdot \sin(\theta) ]
where ( r ) is the radius and ( \theta ) is the angle in radians.
Substitute ( r = 4 ) and ( \theta = -\frac{\pi}{2} ) into the formulas:
[ x = 4 \cdot \cos\left(-\frac{\pi}{2}\right) ] [ y = 4 \cdot \sin\left(-\frac{\pi}{2}\right) ]
Evaluate the trigonometric functions:
[ x = 4 \cdot 0 ] [ y = 4 \cdot (-1) ]
[ x = 0 ] [ y = -4 ]
So, the corresponding rectangular coordinates are ( (0, -4) ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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