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For the function #g(x)=x^3+x^2-6x#, how do you find at least one value of x for which g(x)=0?

Answer 1

Kennedy Adams

# {x : g(x)=0}={-3,0,2}.#

#g(x)=0 rArr x^3+x^2-6x=0.#

# rArr x(x^2+x-6)=0.#

# rArr x{ul(x^2+3x)-ul(2x-6)}=0.........[3xx2=6, 3-2=1].#

# rArr x{x(x+3)-2(x+3)}=0.#

# rArr x(x+3)(x-2)=0.#

Hence, the Desired Set# ={x : g(x)=0}={-3,0,2}.#

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Answer 2

Ethan Adkins

One value is x = 2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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