For the function #f(x) = x^2 - 2x + 1#, how do you solve f(x) = 0?

Answer 1

To solve ( f(x) = 0 ) for the function ( f(x) = x^2 - 2x + 1 ), you would set the function equal to zero and solve for ( x ) by factoring, completing the square, or using the quadratic formula. In this case, the function factors as ( (x - 1)^2 = 0 ), so the solution is ( x = 1 ).

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Answer 2

Eli Assouline

#x=1#

If #f(x)=x^2-2x+1# when #f(x)=0# then #x^2-2x+1=0# and, factoring the left side,: #(x-1)^2=0# #rArr x-1=0# #rArr x=1#

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.