For the following reaction delta H = 2816 kJ. 6 CO2 (g) + 6 H2O (l) <---> C6H12O6 (s) + 6 O2 (g). What will be the effect on the equilibrium yield of C6H12O6 (s) if: ?
a.) the pressure of CO2 (g) is increased?
b.) the temperature is increased?
c.) CO2 (g) is removed from the reactor?
d.) C6H12O6 (s) is removed from the reactor?
e.) O2 (g) is removed from the reactor?
f.) a catalyst is added?
g.) the total pressure is decreased?
a.) the pressure of CO2 (g) is increased?
b.) the temperature is increased?
c.) CO2 (g) is removed from the reactor?
d.) C6H12O6 (s) is removed from the reactor?
e.) O2 (g) is removed from the reactor?
f.) a catalyst is added?
g.) the total pressure is decreased?
Here's what I get.
This question is an exercise in the application of Le Châtelier's Principle, which states that if we apply a stress to a system at equilibrium, the system will respond in such a way as to relieve the stress.
We can treat the heat as if it were a reactant:
(b) Increase the temperature.
The position of equilibrium will shift to the right to get rid of the added heat. The yield will increase.
No effect. The addition or removal of a solid does not affect the position of equilibrium.
(f) Adding a catalyst
No effect. The addition of a catalyst does not affect the position of equilibrium. It just speeds up the reaction.
(g) Increasing the total pressure
No effect. There are 6 mol of gas on each side of the equation, so the system is unable to relieve the pressure by moving in either direction.
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You haven't provided the specific change or condition that would affect the equilibrium yield of C6H12O6 (s). Could you please provide the specific condition or change you'd like to know about? Examples include changes in temperature, pressure, concentration, or the addition of a catalyst.
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