For #g(s)=2s+4#; how do you find g(1),g(-7),and g(6)?
To find g(1), g(-7), and g(6) for the function g(s) = 2s + 4, substitute the given values of s into the function:
g(1) = 2(1) + 4 = 2 + 4 = 6 g(-7) = 2(-7) + 4 = -14 + 4 = -10 g(6) = 2(6) + 4 = 12 + 4 = 16
By signing up, you agree to our Terms of Service and Privacy Policy
You just fill in the number and calculate
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- How do you find the value of 3x-2 when x=4?
- What is #0.24# in percent form?
- How do you find the domain and range for #y=sqrt(x+4)#?
- A father is four times as old as his daughter. In 6 years, he will be three times as old as she is. How old is the daughter now?
- How do you use order of operations to simplify #9/4 times 2/3 + 4/5 times 5/3#?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7