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For an X-linked recessive trait, 9% of the females in the population are affected. What percent of the males would be affected? What percentage of the population is represented by the carriers?

Answer 1

Julian Aguilar

Castle Hardy Weinburg exclusively for women:

#1 = q^2 + 2*p*q + p^2#

#1 = q + p#

where it tells you that #p^2 = 0.09#, so

#p = 0.3" "# and #" "q = 0.7#.

Since carriers are female heterozygotes,

#"heterozygous" = 2 * p * q = 2 * 0.3 * 0.7 = 0.42#

#42%# of females are carriers.

It is the first section.

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Answer 2

Connor Abernathy

For X-linked recessive traits, males are more commonly affected. If 9% of females are affected, then the frequency of affected males would be approximately twice that, or 18%. The carriers, individuals who have one copy of the recessive allele but do not express the trait, would represent about 36% of the population.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.