For a standard deck of 52 what is the probability of randomly picking either an ace or a king?

Question

Eli Assouline · Accepted Answer

#2/13~=15.4%#

There are 13 ordinal cards (Ace - 10, Jack, Queen, King) in each of 4 suits (Spade, Club, Diamond, Heart) and so there are 52 cards in a standard deck (#4xx13=52#).

If we pick a random card, what is the probability of picking either an Ace or King?

Probability measures the percentage or fraction of the time we'll achieve a certain result (in a fraction, this is the numerator) over the total number of possible outcomes (this is the denominator). In this question, there are 8 cards that will satisfy our conditions (4 Kings, 4 Aces) and 52 total outcomes, so we get:

#8/52=4/26=2/13~=15.4%#

Ethan Adkins · Answer

undefined There are 4 aces and 4 kings in a standard deck of 52 cards.

The probability of randomly picking either an ace or a king can be calculated as follows:

$$ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} $$

$$ \text{Probability} = \frac{4 + 4}{52} = \frac{8}{52} = \frac{2}{13} $$

So, the probability of randomly picking either an ace or a king from a standard deck of 52 cards is $ \frac{2}{13} $.