# Find the area of the triangle ABC with sides 15cm, 15 cm and 24 cm?

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To find the area of a triangle when the lengths of all three sides are known, you can use Heron's formula. Heron's formula states that the area (A) of a triangle with side lengths (a), (b), and (c) is given by:

[ A = \sqrt{s(s - a)(s - b)(s - c)} ]

where (s) is the semi-perimeter of the triangle, calculated as:

[ s = \frac{a + b + c}{2} ]

Given that the sides of the triangle ABC are 15 cm, 15 cm, and 24 cm, we can calculate the semi-perimeter (s) as:

[ s = \frac{15 + 15 + 24}{2} = \frac{54}{2} = 27 \text{ cm} ]

Now, we can use Heron's formula to find the area:

[ A = \sqrt{27(27 - 15)(27 - 15)(27 - 24)} ] [ A = \sqrt{27 \times 12 \times 12 \times 3} ] [ A = \sqrt{11664} ] [ A = 108 \text{ cm}^2 ]

Therefore, the area of the triangle ABC with sides 15 cm, 15 cm, and 24 cm is 108 square centimeters.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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