Find all angles a in the interval [0degrees, 360 degrees] such that sin^2asina =0?
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To find all angles ( a ) in the interval ([0^\circ, 360^\circ]) such that ( \sin^2 a  \sin a = 0 ), we first note that this equation can be factored as ( \sin a (\sin a  1) = 0 ).
Now, we solve for ( \sin a = 0 ) and ( \sin a  1 = 0 ) separately.

For ( \sin a = 0 ), this occurs when ( a = 0^\circ ) and ( a = 180^\circ ).

For ( \sin a  1 = 0 ), we have ( \sin a = 1 ). However, ( \sin a = 1 ) only occurs at ( a = 90^\circ ).
Thus, the solutions for ( a ) in the interval ([0^\circ, 360^\circ]) such that ( \sin^2 a  \sin a = 0 ) are ( a = 0^\circ, 90^\circ, ) and ( 180^\circ ).
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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