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Find a quadratic equation whose roots are (7,-5)?write in standard form

Answer 1

Savannah Anderson

#x^2-2x-35#

A quadratic function in standard form is written: #ax^2+bx+c#, where #a, b and c# are real coefficients.

Let our quadratic function be #f(x)#

The roots of #f(x)# are those values of #x# for which #f(x)=0#

Here we are told that #+7 and -5# are roots.

This implies that #(x-7) and (x+5)# are factors of #f(x)#

Hence, #f(x) = (x-7)(x+5)#

#:. f(x) = x^2-2x-35#

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Answer 2

Genesis Allen

The quadratic equation with roots (7, -5) in standard form is:

( y = (x - 7)(x + 5) )

Expanding this equation:

( y = x^2 - 7x + 5x - 35 )

Combining like terms:

( y = x^2 - 2x - 35 )

So, the quadratic equation in standard form is ( y = x^2 - 2x - 35 ).

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Answer from HIX Tutor

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