Exactly 5.00 L of air at -50.0°C is warmed to 100.0°C. What is the new volume if the pressure remains constant?

Answer 1

Given your reaction conditions, your volume of gas is in a piston. The gas should expand to a #~=8*L# volume.

I think you have asked this question before; it is still suspect because we must assume that the gas is enclosed in a container whose volume can change, i.e. a piston.

Charles' Law states that #"Volume "prop" Temperature"#, i.e. #VpropT#, or #V=kT#.

Solving for #k#, #V_1/T_1=V_2/T_2#, and here we must use #" Absolute Temperature"# #=# #""^@C + 273.15*K#.

#V_2=(V_1T_2)/T_1# #=# #(5.00*Lxx373.15*K)/(223.15*K)# #=# #??L#

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Answer 2

Owen Ambrose

The new volume of air would be approximately 5.44 L.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.