Evie's cell phone plan cost $35 a month with an additional 10 cents per minute for any minutes over 500 minutes per month. Evie was charged $37.20 in January, how many minutes did Evie use on her cell phone plan that month?

Answer 1

#522# minutes

The difference between $35 and the charge is made up by the minutes more than 500.

#$37.20 -$35 = $2.20#
#$2.20 = 220 # cents
#220 div 10 = 22# extra minutes
Evie used #500+22 = 522# minutes on her phone plan
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Answer 2

To find out how many minutes Evie used on her cell phone plan in January, we need to solve the following equation:

[ 35 + 0.10 \times (x - 500) = 37.20 ]

Where:

  • ( x ) represents the total number of minutes Evie used in January.

First, subtract the fixed monthly cost from the total amount charged to find the additional cost due to extra minutes:

[ 37.20 - 35 = 2.20 ]

Then, divide this additional cost by the per-minute rate to find the number of extra minutes:

[ 2.20 / 0.10 = 22 ]

Finally, add these extra minutes to the 500 base minutes to find the total number of minutes used:

[ 500 + 22 = 522 ]

Therefore, Evie used 522 minutes on her cell phone plan in January.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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