Evaluate #dy/(d (theta)# when #theta# = #pi# for #y= 2ln2 (theta) -cos^2 2(theta)# ?
The answer is
The function is
We need
Therefore, the derivative is
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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- How do you differentiate #y= arctan(x - sqrt(1+x^2))#?
- How do you find the derivative of #y= x(1-x^2)^(1/2) + arccos(x)#?

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