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Electromagnetic waves of an unknown source are received and it is discovered that a photon of this radiation has energy of 6.63*10^-19 J?

Answer 1

Lily Adams

I'm assuming that you are looking for the frequency of the wave....

In that case, we use the equation:

#color(white)(aaaaaaaaaaaa)color(blue)(barul(|E=hf|))#

where:

#E# is the energy in joules

#h# is Planck's constant, #6.63*10^-34 \ "J s"#

#f# is the frequency in hertz

Rearranging for frequency, the equation becomes:

#f=E/h#

#=(6.63*10^-19color(red)cancelcolor(black)"J")/(6.63*10^-34color(red)cancelcolor(black)"J""s")#

#=10^15 \ "s"^-1#

#=10^15 \ "Hz" \ (because 1 \ "Hz"=1 \ "s"^-1)#

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.