Does zinc react with NaOH when its not heated?

Answer 1

Zinc is an active metal.......

It will slowly be oxidized by hydroxide, to give #Zn^(2+)# and dihydrogen gas......

Additionally, we could write the redox pair.

#Zn rarr Zn^(2+) + 2e^(-)# #(i)#
#H_2O + e^(-) rarr 1/2H_2(g)uarr + HO^-# #(ii)#
And so we take #(i) + 2xx(ii)# to get......
#Zn(s) + 2H_2O(l)rarrZn^(2+) + 2HO^(-) + H_2(g)#
In conc. hydroxide it would probably from the zincate ion, #[Zn(OH)_4]^(2-)#.....
#Zn(s) + 2HO^(-) + 2H_2O(l) rarrZn(OH)_4^(2-) +H_2(g)uarr#
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Answer 2

When zinc is not heated, it does not react with NaOH.

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Answer 3

No, zinc does not react with NaOH when it's not heated. The reaction between zinc and sodium hydroxide typically requires heating to initiate the reaction.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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