Does the altitude of an isosceles triangle bisect the base? Please explain.
Let's consider the isosceles triangle of the figure below
CD is the altitude from vertex C to base AB. Hence the triangles
ADC and CDB are equal because the have two sides equal and one angle equal (SAS) then AD=DB hence the altitude bisects the base.
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Yes, the altitude of an isosceles triangle bisects the base. This property holds true for all isosceles triangles. When an altitude is drawn from the vertex angle of an isosceles triangle to the midpoint of the base, it divides the base into two equal segments. This is because in an isosceles triangle, the base angles are congruent, and the altitude drawn from the vertex angle bisects the base, creating two congruent right triangles. Therefore, the altitude of an isosceles triangle does indeed bisect the base.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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