# Does anyone know of a theorem or equation that will determine how many diagonals a polygon has, without having to do a drawing to see how many there are?

where, n is the *number of sides*

*For example ...*

*triangle: #3xx(3-3)/2=0# diagonals*

*pentagon: #5xx(5-3)/2=5# diagonals*

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*hope that helped*

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*Answer 2Sign up to view the whole answerSign up with email*

Yes, there is a formula to determine the number of diagonals in a polygon without drawing it. The formula is:

[ \text{{Number of diagonals}} = \frac{{n(n-3)}}{2} ]

Where ( n ) represents the number of sides of the polygon.

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*Answer from HIX Tutor*

*When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.*

*When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.*

*When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.*

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