Difficult molecular formula question? (See below)

The following appeared on my practise test:
You discover the formula of a new compound to be #C_(4y)H_(7y)O_y# , where y is a unit positive integer between 1 and 9; for example, if y = 2, then the molecular formula would be #C_42H_72O_2#. Determine the molecular formula if the molar mass ofhe compound is 725.22 g/mol. Show all work – maximum marks will be rewarded for solving using a single equation.

Answer 1
The molecular formula of the given compound is #C_(4y)H_(7y)O_y#.Here y represents the unit place of a number as evident from the given example. 4 and 7 represent the tens place of the number of Carbon atoms and the number of H atoms in the molecule.
Hence molecular formula of the compound should actually be represnted as follows #C_((4*10+y))H_((7*10+y))O_y#
Using atomic masses of constituent elements the caculated molar mass becomes #12(40+y)+1(70+y)+16y# #=550+29yg"/mol"#

Equating this with the given molar mass we get

#550+29y=725.22# #=>y=175.22/29~~6#

So the molecular formula of the compound is

#C_((4*10+y))H_((7*10+y))O_y#
#=C_((4*10+6))H_((7*10+6))O_6#
#=C_46H_76O_6#
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Answer 2

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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