# Determine the specific heat of unknown metal from the fact that 6.40 * 10-2kj are needed to raise the temperature of 15g of unknown metal from 22 degrees Celsius to 33 degrees Celsius?

Now we plug everything we know from the equation in:

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To determine the specific heat (( c )) of the unknown metal, you can use the formula:

[ q = m \times c \times \Delta T ]

Where: ( q ) = heat energy (in joules) ( m ) = mass of the metal (in grams) ( c ) = specific heat of the metal (in ( \text{J/g°C} )) ( \Delta T ) = change in temperature (in °C)

Given: ( q = 6.40 \times 10^{-2} \text{ kJ} = 6.40 \times 10^{-2} \times 10^3 \text{ J} = 64 \text{ J} ) ( m = 15 \text{ g} ) ( \Delta T = 33°C - 22°C = 11°C )

Substituting these values into the formula:

[ 64 \text{ J} = 15 \text{ g} \times c \times 11°C ]

Solving for ( c ):

[ c = \frac{64 \text{ J}}{15 \text{ g} \times 11°C} = \frac{64}{165} \text{ J/g°C} \approx 0.387 \text{ J/g°C} ]

The specific heat of the unknown metal is approximately ( 0.387 \text{ J/g°C} ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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