Determine how many liters of nitrogen will be required to produce 214.4 liters of ammonia? The balanced equation for this reaction is: #3"H"_2(g) + "N"_2(g) -> 2"NH"_3(g)# ?

Answer 1

#"107.2 L"#

The idea here is that if all the gases that take part in the reaction are kept under the same conditions for pressure and temperature, then you can treat the mole ratios that exist between them as volume ratios.

#3"H"_ (2(g)) + "N"_ (2(g)) -> 2"NH"_ (3(g))#
The balanced chemical equation tells you that in order to produce #2# moles of ammonia, the reaction must consume #3# moles of hydrogen gas and #1# mole of nitrogen gas.
If all three gases are kept under the same conditions for pressure and temperature, you can say that in order for the reaction to produce #"2 L"# of ammonia, ti must consume #"3 L"# of hydrogen gas and #"1 L"# of nitrogen gas.

This means that your reaction will require

#214.4 color(red)(cancel(color(black)("L NH"_3))) * "1 L N"_2/(2color(red)(cancel(color(black)("L NH"_3)))) = color(darkgreen)(ul(color(black)("107.2 L N"_2)))#

The answer is rounded to four sig figs.

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Answer 2

To produce 214.4 liters of ammonia, you would need 357.33 liters of nitrogen.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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