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Could you show me this recurrence question 7 ?

Answer 1

Sophie Adams

#a_3=362#

#"substitute previous values into "a_n=3a_(n-1)^2-1#

#rArra_2=3xxa_1^2-1=3xx2^2-1=12-1=11#

#a_3=3xxa_2^2-1=3xx11^2-1=363-1=362#

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Answer 2

Lincoln Anderson

I get #362#.

We got: #a_1=2, a_n=3a_(n-1)^2-1#

#:.a_2=3a_1^2-1#

#=3*4-1#

#=11#

Repeating for #a_3#, we get

#a_3=3a_2^2-1#

#=3*11^2-1#

#=3*121-1#

#=363-1#

#=362#

I hope this was clear!

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Answer 3

Lily Anderson

Certainly, could you please provide the specific details or context regarding "recurrence question 7" so that I can accurately address your inquiry?

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.