# Convert the equation y =#-(sqrt(3)/(3))x# to polar form?

This is my first time attempting converting from rectangular to polar, so please feel free to correct If I am wrong

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To convert the equation ( y = -\frac{\sqrt{3}}{3}x ) to polar form, we use the relationships between Cartesian (x, y) and polar (r, θ) coordinates:

[ x = r \cos(\theta) ] [ y = r \sin(\theta) ]

First, substitute ( x ) and ( y ) in the equation ( y = -\frac{\sqrt{3}}{3}x ) with their polar forms:

[ r \sin(\theta) = -\frac{\sqrt{3}}{3} r \cos(\theta) ]

Next, divide both sides by ( r ) to isolate ( \theta ):

[ \frac{\sin(\theta)}{\cos(\theta)} = -\frac{\sqrt{3}}{3} ]

Now, simplify the left side using the tangent function:

[ \tan(\theta) = -\frac{\sqrt{3}}{3} ]

Finally, find the polar form by taking the arctangent (inverse tangent) of both sides:

[ \theta = \arctan\left(-\frac{\sqrt{3}}{3}\right) ]

This gives the polar form of the equation.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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