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Convert the equation 6x+5y+6=0 to polar form?

Answer 1

Caroline Adams

#r= -6/(6costheta+5sintheta)#

#6x+5y+6=0#

The conversion from Rectangular to Polar: #x=rcostheta# #y=rsintheta#

Substitute and solve for #r# #6(rcostheta)+5(rsintheta)+6= 0#

Simplify and factor out #r# #6rcostheta+5rsintheta+6= 0# #6rcostheta+5rsintheta= -6# #r(6costheta+5sintheta)= -6#

Solve for #r# #r= -6/(6costheta+5sintheta)#

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Answer 2

Quinn Anderson

To convert the equation (6x + 5y + 6 = 0) to polar form, we can use the following relationships:

(x = r\cos(\theta)) and (y = r\sin(\theta)).

Substituting these into the equation gives:

(6(r\cos(\theta)) + 5(r\sin(\theta)) + 6 = 0).

Now, let's simplify:

(6r\cos(\theta) + 5r\sin(\theta) + 6 = 0).

This equation is in polar form.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.