Consider an electromagnetic wave with a frequency of #3.0xx10^10# #Hz#. What is its wavelength? What is the energy of one photon of this light?

Answer 1

#lambda = c/f=(3.0xx10^8)/(3.0xx10^10)=10^-2# #m#

#E=hf=6.63xx10^-34xx3.0xx10^10=1.99xx10^-23# #J#

For electromagnetic radiation:

#c=flambda# where #c# is the speed of light, #f# is the frequency, #lambda# is the wavelength.

Rearranging:

#lambda = c/f=(3.0xx10^8)/(3.0xx10^10)=10^-2# #m#

The energy of a photon is given by:

#E=hf# where #h# is Planck's constant, #6.63xx10^-34# #m^2kgs^-1#
#E=hf=6.63xx10^-34xx3.0xx10^10=1.99xx10^-23# #J#
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Answer 2

The electromagnetic wave's wavelength can be found using the following formula: wavelength = speed of light / frequency − wavelength = 3.00 x 10^8 m/s / 3.0 x 10^10 Hz ≈ 1.0 x 10^-2 meters The energy of a single photon can be found using the following formula: energy of a single photon = Planck's constant * frequency ≒ energy of one photon = 6.626 x 10^-34 Js * 3.0 x 10^10 Hz ≈ 2.0 x 10^-24 Joules

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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