Complete the reaction: #HCN + 2H_2O -> ?# Also, how is oxamide prepared? What is the reaction for its preparation?

Answer 1

cyanide on hydrolysis gives carboxylic acids.

HCN + 2H2O → HCOOH

steps: (1) #H-C-=N + H_"2"O → H-C(OH)=NH# (2) #H-C(OH)=NH + H_"2"O →H-C(OH)_"2"NH2#
(3) #H-C(OH)_"2"NH2# will further give HCOOH + NH3
#(CN)_"2"+ H2O+ HCl rarr NH2-CO-CO-NH2#

(APPLYING THE ABOVE PROCEDURE)

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Answer 2

HCN + 2H₂O → CN⁻ + 2H₃O⁺

Oxamide is prepared by the reaction of oxalic acid with ammonia:

H₂C₂O₄ + 2NH₃ → (NH₂)₂C₂O₂ + 2H₂O

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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