Circle A has a center at #(9 ,-2 )# and a radius of #4 #. Circle B has a center at #(-2 ,6 )# and a radius of #2 #. Do the circles overlap? If not, what is the smallest distance between them?

Answer 1

no overlap , 7.6

The first step is to calculate the distance betwee the centres using the #color(blue)" distance formula "#
#d = sqrt((x_2-x_1)^2+(y_2-y_1)^2)#
where#(x_1,y_1) " and "(x_2,y_2)" are 2 coord points "#
let#(x_1,y_1)=(9,-2)" and "(x_2,y_2) =(-2,6)#

substitute values into distance formula

#d=sqrt((-2-9)^2+(6-(-2))^2) = sqrt(121+64)=sqrt185 ≈ 13.6#

now radius of circle A + radius of circle B = 4+2 = 6

Since 6 < 13.6 there is no overlap

and distance between them is 13.6 - 6 = 7.6

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Answer 2

The circles A and B do not overlap. The distance between their centers is greater than the sum of their radii. The smallest distance between the circles is the difference between the distance between their centers and the sum of their radii.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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