[CH3CCH in presence of H2O, H2 s o4 and mercuric sulphate] What is the mechanism of formation of intermediate and product of the reaction? ANS:The intermediate is acetone and product is propnaldehyde

Answer 1

The product is acetone and the intermediate is propanal.

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Answer 2

The given reaction involves hydration of propyne (CH3CCH) in the presence of H2O, H2SO4, and mercuric sulfate. The mechanism includes the formation of an enol intermediate (CH3CCHOH) followed by tautomerization to produce acetone. The final product is propionaldehyde.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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