# Can you tell that for example it's an equation #y=2x^2-6x+5# And question is to find the set values of x for which y>13 So in it answers are x<-1 and x>4 How do we know that x is greater or less than -1 or 4 as when we solve it on calculator?

Please see below.

There are two ways that this could go.

graph{(2x^2-6x+5-y)(y-13)=0 [-3.75, 6.25, 10.1, 15.1]}

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See explanation

set

As the

By changing the above from > to = we can solve for the points where

To find the critical points write

The required

For this to work we have

Thus we have

So for

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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- How do you solve #abs(4/3x+7)+5=14#?

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