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Can you solve this problem in Mechanics?

Answer 1

Lily Adams

#x(t) = (x_e-(gm)/k tan(a))(cos(sqrt(k/m)t)-1) #

Considering the movement projected over the ramp, applying Newton's second law and making #alpha = dy/dx=a#

#-m g sin(alpha)-k(x-x_e)cos(alpha)=m ddotx cos(alpha)# or

#ddot x+k/m x+g tan(alpha)-kx_ecos(alpha)=0#

This second order linear differential equation has the general solution.

#x(t)=x_e+C_1 Cos(sqrt[k/m] t) + C_2 sin(sqrt[k/m] t) - ( g m tan(alpha))/k#

#C_1,C_2# are determined according to the initial conditions:

#{(x(0)=x_0),(dot x(0)=0):}#

so finally

#x(t) = (x_e-(gm)/k tan(a))(cos(sqrt(k/m)t)-1) #

The #y(t)# position formulation, is let as an exercise to the reader.

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Answer 2

Sebastian Acosta

Certainly, please provide the Mechanics problem, and I will assist you in solving it.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.