Can you help me with this? 20 g of glucose is dissolved in 150 g of water. Calculate the molarity, molality & mole fraction of glucose in solution.

Question

Peyton Adams · Accepted Answer

Here's how you can go about solving this one.

The solution's molarity can only be ascertained with the solution's volume, but the problem provides all the information required to solve for the solution's molality and mole fraction. To calculate the volume, you must first ascertain the density of the solution by calculating its percent concentration by mass. #"%w/w" = m_"solute"/m_"solution" * 100# The mass of the solution in your situation will be #m_"solution" = m_"glucose" + m_"water"# #m_"solution" = 20 + 150 = "170 g"# This implies that you receive #"%w/w" = (20cancel("g"))/(170cancel("g")) * 100 = "11.8%"# Consequently, this solution's density will be The link to the application editorials is https://tutor.hix.ai #rho = "1.045 g/mL"# Calculate your moles using the molar mass of glucose. #20cancel("g") * "1 mole glucose"/(180.16cancel("g")) = "0.111 moles glucose"# The volume of the solution will be #170cancel("g") * "1 mL"/(1.045cancel("g")) = "162.7 mL"# Its molarity is indicated by this, so remember to convert the volume to liters! #C = n/V = "0.111 moles"/(162.7 * 10^(-3)"L") = color(green)("0.68 M")# The number of moles of solute divided by the mass of the solvent, expressed in kilograms, is the definition of a solution's molality. #b = n/m_"water" = "0.111 moles"/(150 * 10^(-3)"kg") = color(green)("0.74 molal")# Once again, use the molar mass of water to find the mole fraction of sucrose. You also need to know how many moles of water are present. #150cancel("g") * "1 mole water"/(18.02cancel("g")) = "8.24 moles water"# There are a total of moles in the solution. #n_"total" = n_"glucose" + n_"water"# #n_"total" = 0.111 + 8.24 = "8.351 moles"# This implies that the number of moles of sucrose divided by the total number of moles in the solution, or the mole fraction of sucrose, will be #chi_"sucrose" = n_"sucrose"/n_"total" = (0.111cancel("moles"))/(8.351cancel("moles")) = color(green)("0.013")# SIDE NOTE: Although you only provided one sig fig for the mass of glucose, I've left the values rounded to two sig figs.

Xavier Avery · Answer

undefined The molarity is approximately 0.56 M, molality is approximately 0.53 m, and the mole fraction of glucose is approximately 0.018.

Can you help me with this? 20 g of glucose is dissolved in 150 g of water. Calculate the molarity, molality &amp; mole fraction of glucose in solution.

Can you help me with this? 20 g of glucose is dissolved in 150 g of water. Calculate the molarity, molality & mole fraction of glucose in solution.